Hydrostatic Law MCQ Quiz in मराठी - Objective Question with Answer for Hydrostatic Law - मोफत PDF डाउनलोड करा
Last updated on Apr 4, 2025
Latest Hydrostatic Law MCQ Objective Questions
Top Hydrostatic Law MCQ Objective Questions
Hydrostatic Law Question 1:
A partially filled tank is being carried on a truck which is moving with constant acceleration. The water surface in the tank will
Answer (Detailed Solution Below)
Hydrostatic Law Question 1 Detailed Solution
Hydrostatic Law Question 2:
The ratio of pressure intensity at a point and specific weight of the fluid at that point is called _______.
Answer (Detailed Solution Below)
Hydrostatic Law Question 2 Detailed Solution
Explanation:
Pressure Head:
The ratio of pressure intensity at a point and the specific weight of the fluid at that point is called pressure head
ressure head =
Hydraulic head/Piezometric head:
Hydraulic head or piezometric head is a specific measurement of liquid pressure above a vertical datum. It is usually measured.
The sum of the pressure head and datum is known theas piezometric head. It is given by:
The total energy of a flowing fluid can be represented in terms of head, which is given by -
Hydrostatic Law Question 3:
The law which states that the rate of increase of pressure in a vertical direction is equal to weight density of the fluid at that point is called as ________.
Answer (Detailed Solution Below)
Hydrostatic Law Question 3 Detailed Solution
Explanation:
- According to Hydrostatic Law, the rate of increase of pressure in a vertical direction is equal to the weight density of the fluid at that point when the fluid is stationary.
- The pressure at any point in a fluid at rest is obtained by the Hydrostatic Law which states that the rate of increase of pressure in a vertically downward direction must be equal to the specific weight of the fluid at that point.
Thus, The rate of increase of pressure in a vertically downward direction is equal to Specific weight
Hydrostatic Law Question 4:
The relationship between pressure (p) and depth of fluid (h) in the static condition is:
Answer (Detailed Solution Below)
Hydrostatic Law Question 4 Detailed Solution
Explanation:
According to Hydrostatic Law, the rate of increase of pressure in a vertical direction is equal to weight density of the fluid at that point when the fluid is stationary.
The pressure at any point in a fluid at rest is obtained by the Hydrostatic Law which states that the rate of increase of pressure in a vertically downward direction must be equal to the specific weight of the fluid at that point.
P = ωh
Hence, p ∝ h
Thus, pressure in a stationary water column increases with depth and varies linearly and does not depend upon viscosity.
It indicates that a negative pressure gradient exists upward along any vertical.
Hydrostatic Law Question 5:
The pressure at a point inside a liquid does not depend on which of the following?
Answer (Detailed Solution Below)
Hydrostatic Law Question 5 Detailed Solution
Explanation:
Hydrostatic law:
In a static fluid, the pressure depends on the vertical depth from the surface and it is independent of its shape and size of the container.
The pressure at a point inside a liquid is given by,
P = ρ × g × h
Where, h = Vertical height of the fluid column, ρ = Density of the liquid and
g = Acceleration due to gravity (9.81 m/s2)
- According to Hydrostatic law, the pressure at a point depends upon vertical depth from the liquid surface and independent of the shape of the container in a static fluid.
- In the given containers A and B, the point P lie at the same depth d and pressure varies only in the vertical direction.
- Hence the pressure at point P is the same in both containers A and B irrespective of the shape.
Example:
Pressure in A, B, and C, h height bellow from the water surface is the same.
Hydrostatic Law Question 6:
A hydraulic jack is used to compress a spring as shown in fig. stiffness of spring is 105 N/m. By applying a pressure ‘p’ in the hydraulic cylinder, the spring gets compressed by 10 mm. The cross-sectional area of the piston is 25 cm2. The applied pressure ‘p’ is
Answer (Detailed Solution Below)
Hydrostatic Law Question 6 Detailed Solution
Concept:
The pressure acts on the piston is, P = FA
where, F = force acts on piston, A = cross-section ara of piston
Calculation:
Given:
A = 25 cm2, k = 105 N/m, x = 10 mm = 10 × 10-3 m
Force on piston (spring)
F = kx = 105 × 10 ×10-3 = 1000 N
Now pressure force by piston = P × 25 × 10-4
On equating
P × 25 × 10-4 = 1000 N
Hydrostatic Law Question 7:
If barometric pressure on a mountain top is 735 mm of mercury, then the pressure (in N/m2) will be:
Answer (Detailed Solution Below)
Hydrostatic Law Question 7 Detailed Solution
Concept:
Pabsolute = Patmospheric + Pgauge
The pressure at any point in a static fluid is obtained by Hydro-static law which is given by-
∴ P = -ρgz
P increases when we go down (z negative) and decreases when we go up (z positive).
where P = pressure above atmospheric pressure and h = height of the point from the free surface.
Calculation:
Given:
h = 735 mm of Mercury, ρmer = 13600 Kg/m3
∴ P = ρmer × g × h
⇒ P = 13600× 9.81× 0.735 = 98060.76 N/m2
Hydrostatic Law Question 8:
Point X is 10 m below the free surface of a liquid and point Y is 12 m below the free surface of the same liquid. The correct relationship for the pressure at points X and Y is _________ .
Answer (Detailed Solution Below)
Hydrostatic Law Question 8 Detailed Solution
Explanation:
Concept:
Hydrostatic Law: This law states that the rate of increase of pressure in the vertical direction is directly proportional to the weight density of fluid at that point.
Note:
- In a vertically downward direction, pressure variation is taken as positive.
- In a vertically upward direction, pressure variation is taken as negative.
Absolute pressure: It is the sum of atmospheric pressure and gauge pressure.
Calculation:
Given:
hX = 10 m, hY = 12 m
So,
similarly,
The absolute pressure depends upon the distance of the point from the free surface.
Thus, option (1) is correct answer.
Hydrostatic Law Question 9:
Which of the following law states that the pressure applied in a confined incompressible fluid gets transmitted throughout the liquid without any change in all the directions?
Answer (Detailed Solution Below)
Hydrostatic Law Question 9 Detailed Solution
CONCEPT:
- According to Blaise Pascal, a French scientist observed that the pressure in a fluid at rest is the same at all points if they are at the same height and it is termed Pascal’s Law.
- i.e., the pressure exerted by the fluid on an object at a certain height will be the same in all directions.
and hence it can be expressed as
- From the above fig., we can see that the force against the area within a fluid at rest will always experience pressure perpendicular to its surface area, and the object will experience equal pressure throughout the surface.
- And there are a number of devices, such as hydraulic lifts and hydraulic brakes, which are based on Pascal’s law, these devices used fluids for transmitting pressure.
EXPLANATION:
- From the above explanation we can see that according to Pascal’s law, pressure in a fluid at rest is the same at all points if they are at the same height.
- This means option one is correct among all.
Hydrostatic Law Question 10:
What will be the atmospheric pressure at a location where the barometric reading is 750 mm Hg and the gravitational acceleration is g = 9.81 m/s2? Assume the density of mercury to be 13,600 kg/m3.
Answer (Detailed Solution Below)
Hydrostatic Law Question 10 Detailed Solution
To find the atmospheric pressure we can use the formula:
P = ρgh
where:
P is the atmospheric pressure
ρ is the density of the fluid (mercury in this case)
g is the gravitational acceleration
h is the height or depth of the fluid (the barometric reading)
Calculations:
According to the data given:
ρ = 13,600 kg/m3 (density of mercury) g = 9.81 m/s2 (gravitational acceleration) h = 750 mm of Hg = 0.75 m (converted from mm to m)
Substituting the value:
P = 13,600 kg/m3 × 9.81 m/s2 × 0.75 m = 100059 Pa
Or we can say that the pressure is approximately 100.06 kPa. Since the standard unit of atmospheric pressure is kPa (kilopascal), this should be the most appropriate answer. Therefore, the correct option is: 100.06 kPa