Polynomial Rings and Irreducibility Criteria MCQ Quiz in मल्याळम - Objective Question with Answer for Polynomial Rings and Irreducibility Criteria - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

Solution -  

Option 1) 

Given, polynomial  has no root in  

so it is irreducible .

Option 2) 

Given, polynomial  has no root in Q 

so it is irreducible 

Option 3) 

As every polynomial of odd degree 

has atleast one real root in R so it is reducible.

Option 4) 

let q(x) =  

taking p= 101 here p divides  

then , By einstein Criteria Q[x] is irreducible polynomial. 

Therefore, Correct Option (s) are Option 1), 2) and 4).