Problem on Age MCQ Quiz - Objective Question with Answer for Problem on Age - Download Free PDF

Last updated on Jun 17, 2025

Problem on Age objective question answers often leave the candidates confused in making the correct equations and getting to the correct answer. The only solution to this problem is to practice Problem on Age MCQs Quiz as much as one can. Check out this set of questions selected by the Testbook team and practice Problem on Age objective questions right away. These questions also come with solutions and explanations of the given problems as well as some tips, tricks and strategies to save time while solving Problems on Age MCQs Quiz.

Latest Problem on Age MCQ Objective Questions

Problem on Age Question 1:

4 years ago, the age of Garvit was three times that of Yuvansh, but one year ago the age of Garvit was two times that of Yuvansh. What is the difference between the ages of Garvit and Yuvansh?

  1. 13 years
  2. 11 years
  3. 7 years
  4. 6 years
  5. None of the above

Answer (Detailed Solution Below)

Option 4 : 6 years

Problem on Age Question 1 Detailed Solution

Given:

4 years ago, the age of Garvit was three times that of Yuvansh, but one year ago the age of Garvit was two times that of Yuvansh.

Method used:

Elimination method of linear equation in two variable

Calculation:

Let the present age of Garvit be x years and the present age of Yuvansh be y years.

Then, 4 years ago, x - 4 = 3 × (y - 4)...(1)

And one year ago, x - 1 = 2 × (y - 1) ...(2)

Subtracting (2) from (1),

- 3 = y - 10

y = 7 

Substituting y = 7 in (1),

x = 3 × (7 - 4) + 4 = 13   

∴ The difference between the ages of Garvit and Yuvansh is 13 - 7 = 6 years.

Problem on Age Question 2:

The ratio of the present ages of X and Y is 4 ∶ 5 respectively. After 6 years from now, the ratio of his age will be 6 ∶ 7 respectively. What is the difference between their ages?

  1. 3 years
  2. 5 years
  3. 2 years
  4. 4 years
  5. None of the above

Answer (Detailed Solution Below)

Option 1 : 3 years

Problem on Age Question 2 Detailed Solution

Given:

The ratio of the present ages of X and Y is 4 ∶ 5.

After 6 years, the ratio of their ages will be 6 ∶ 7.

Formula Used:

Let the present ages of X and Y be 4k and 5k respectively.

After 6 years, the ages of X and Y will be (4k + 6) and (5k + 6) respectively.

According to the given condition: (4k + 6) / (5k + 6) = 6 / 7

Calculation:

⇒ (4k + 6) / (5k + 6) = 6 / 7

⇒ 7(4k + 6) = 6(5k + 6)

⇒ 28k + 42 = 30k + 36

⇒ 30k - 28k = 42 - 36

⇒ 2k = 6 ⇒ k = 3

The present ages of X and Y are 4k and 5k respectively.

⇒ X = 4k = 4 × 3 = 12 years

⇒ Y = 5k = 5 × 3 = 15 years

The difference between their ages:

⇒ 15 - 12 = 3 years

The correct answer is option 1, 3 years.

Problem on Age Question 3:

 If the ratio of the ages (in years) of P and Q, 5 years ago was 5 : 7 , then the sum of their ages 5 years from now is _____ years.

  1. 87
  2. 90
  3. 98
  4. 92

Answer (Detailed Solution Below)

Option 4 : 92

Problem on Age Question 3 Detailed Solution

Given:

The ratio of ages of P and Q, 5 years ago = 5 : 7

Formula used:

If the ratio of ages is a : b, then their ages can be represented as:

P's age = 5x, Q's age = 7x (where x is the multiplier)

Sum of their ages after 5 years = (P's age + 5) + (Q's age + 5)

Calculation:

5 years ago, P's age = 5x and Q's age = 7x

⇒ Current ages:

P's age now = 5x + 5

Q's age now = 7x + 5

⇒ After 5 years:

P's age = (5x + 5) + 5 = 5x + 10

Q's age = (7x + 5) + 5 = 7x + 10

⇒ Sum of their ages after 5 years:

(5x + 10) + (7x + 10) = 12x + 20

Now, we will solve this equation using the Options.

Here we will put the value of x as 1, 2 ,3 and so on.

When we put the value of x = 6

We get, (12 × 6) + 20 = 72 + 20 = 92.

∴ The correct answer is Option 4).

Problem on Age Question 4:

Five years ago, the average age of Puneet and Amrita was 15 years. Today the average age of Puneet, Amrita and Renu is 20 years. What will be the age of Renu after 12 years?

  1. 30 years
  2. 32 years
  3. 33 years
  4. 35 years
  5. None of the above

Answer (Detailed Solution Below)

Option 2 : 32 years

Problem on Age Question 4 Detailed Solution

Given:

Five years ago, the average age of Puneet and Amrita was 15 years.

Today the average age of Puneet, Amrita and Renu is 20 years.

Formula used:

Average × number of observation = sum of observation

Calculations:

When, average of Puneet and Amrita before 5 years ago was 15,

Puneet - 5 + Amrita - 5 = 15 × 2

=> Puneet + Amrita = 30 + 5 + 5

=> Puneet + Amrita = 40

Now, again, when average of the three = 20

Puneet + Amrita + Renu = 20 × 3 = 60

=> Renu = 60 - 40 = 20 (putting the summation of Puneet and Amrita)

Required age of Renu after 12 years = 20 + 12 = 32 years

∴ The answer is 32 years.

Problem on Age Question 5:

Present age of Karan is 25 years. After five years, the ratio of age of Karan to Sangeet will be 6 : 7. Find the age of Sangeet age four years ago?

  1. 31
  2. 39
  3. 28
  4. 26
  5. 24

Answer (Detailed Solution Below)

Option 4 : 26

Problem on Age Question 5 Detailed Solution

Given:

Present age of Karan = 25 years

In 5 years, the ratio of age of Karan to Sangeet = 6 : 7

Formula used:

Let the present age of Sangeet = x

After 5 years, age of Karan = 25 + 5 = 30 years

After 5 years, age of Sangeet = x + 5

Calculations:

The ratio of their ages after 5 years = 6 : 7

⇒ (30) / (x + 5) = 6 / 7

⇒ 7 × 30 = 6 × (x + 5)

⇒ 210 = 6x + 30

⇒ 6x = 210 - 30

⇒ 6x = 180

⇒ x = 180 / 6

⇒ x = 30

Present age of Sangeet = 30 years

Age of Sangeet four years ago = 30 - 4 = 26 years

∴ The age of Sangeet four years ago was 26 years.

Top Problem on Age MCQ Objective Questions

The ratio of the present ages of a man and his wife is 5 : 8. After 10 years, the ratio of the man and his wife will be 2 : 3. What will be the ratio of their ages after 20 years?

  1. 9 : 10
  2. 3 : 5
  3. 4 : 5
  4. 7 : 10
  5. 3 : 7

Answer (Detailed Solution Below)

Option 4 : 7 : 10

Problem on Age Question 6 Detailed Solution

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Let the ages of the man and his wife be 5x and 8x respectively.

After ten years,

ratio of the man and his wife will be 2 : 3;

⇒ (5x + 10) / (8x + 10) = 2 : 3

Hence, x = 10

The ages of the man and his wife are 50 and 80 respectively.

∴ The ratio of their ages after 20 years is 70 : 100 = 7 : 10

Four years ago ratio of age of Ram and Rahul is 3 : 4. Ratio of their present age is 17 : 22. What is the present age of Sunil if Ram is 5 years older than Sunil?

  1. 36 years
  2. 29 years
  3. 30 years
  4. 31 years

Answer (Detailed Solution Below)

Option 2 : 29 years

Problem on Age Question 7 Detailed Solution

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Given:

Four years ago age ratio of Ram and Rahul = 3 : 4

Present age ratio of Ram and Rahul = 17 : 22

Calculation:

Four years ago age ratio of Ram and Rahul = 3x : 4x

According to the question

(3x + 4)/(4x + 4) = 17/22

⇒ 22 × (3x + 4) = 17 × (4x + 4)

⇒ 66x + 88 = 68x + 68

⇒ 68x – 66x = 88 – 68

⇒ 2x = 20

⇒ x = 10

Present age of Ram = 3 × 10 = 30 + 4 = 34

Present age of Sunil = 34 – 5 = 29 years 

∴ the correct answer is 29 years.

Shortcut Trick 

Many students ignore to read full question, So please read full question before solving it. 
In the last line of question there is mentioned that Ram is 5 years older than Sunil. 
So if you Calculate Ram's age than you also can calculate Sunil's age.

Karan was born 3 years after his parent's marriage. His father is 6 years older than his mother but 26 years older than Karan who is 12 years of age as on today. At what age did his mother get married?

  1. 20 years
  2. 19 years
  3. 17 years
  4. 18 years

Answer (Detailed Solution Below)

Option 3 : 17 years

Problem on Age Question 8 Detailed Solution

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Given:

Karan was born 3 years after his parent's marriage.

His father is 6 years older than his mother but 26 years older than Karan.

Karan is 12 years of age as on today.

Calculation:

According to question,

⇒ F = 6 + M

⇒ F = 26 + K 

Since now karan is 12 years old so,

⇒ K = 12,

⇒ F = 38,

⇒ M = 32

Now at the time of birth age will be ,

⇒ F = 26

⇒ M = 20 

Since karan was born 3 years after his parents marriage so

Age of motrher = 20 - 3 = 17

∴ 'The correct answer is 17 years.

20 year old Manish is five times as old as his brother Greece. How old will Manish be when he is three times as old as Greece?

  1. 30
  2. 32
  3. 24
  4. 28

Answer (Detailed Solution Below)

Option 3 : 24

Problem on Age Question 9 Detailed Solution

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Given:

Manish age = 20 years

Greece age = 20/5 = 4 years

Let after x years Manish will become three times as old as Greece:

(20 + x) = 3 × (4 + x)

20 + x = 12 + 3x

2x = 8

x = 4

After 4 years Manish's age will be 24 years and Greece's age 8 years.

When Manish's age is 24 years old he became three times as old as Greece.

Hence, the correct answer is "24".

Amita's father was 38 years old when she was born, while her mother was 36 years old when her brother was born who was four years younger than her. What is the difference between the ages of his parents?

  1. 4 years
  2. years
  3. years
  4. years

Answer (Detailed Solution Below)

Option 2 : 6 years

Problem on Age Question 10 Detailed Solution

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Given:

Amita's father was 38 years old when she was born.

Her mother was 36 years old when her brother was born.

Her brother was four years younger than her.

Calculation:

Let the present age of Amita be P years.

So,

The age of her father = (38 + P) years

The age of her brother = (P - 4) years

The age of her mother = 36 + (P - 4) = (32 + P) years

Now, the age difference between her parents = (38 + P) - (32 + P) = 6 years

∴ The difference between the ages of her parents is 6 years.

After 15 years, a man will be just four times as old as he was 15 years ago. What is his present age?

  1. 10 years
  2. 15 years
  3. 20 years
  4. 25 years

Answer (Detailed Solution Below)

Option 4 : 25 years

Problem on Age Question 11 Detailed Solution

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Given:

(Man's age + 15 years) = 4(Man's age - 15 years)

Calculation:

Let the present age of the man be x years

According to the question,

⇒ (x + 15) = 4(x - 15)

⇒ x + 15 = 4x - 60

⇒ 4x - x = 15 + 60

⇒ 3x = 75

⇒ x = 25

∴ The present age of man is 25 years.

Keshav and Danish are friends and the age of Keshav 4 years ago is equal to present age of Danish. After six years the ratio of their age will become 19 ∶ 17. What is the sum of their ages?

  1. 45 years
  2. 50 years
  3. 60 years
  4. 70 years

Answer (Detailed Solution Below)

Option 3 : 60 years

Problem on Age Question 12 Detailed Solution

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Let the ages of Keshav and Danish after six years be 19x and 17x respectively

⇒ Present age of Keshav = (19x - 6) years

⇒ Present age of Danish = (17x - 6) years

According to question, age of Keshav 4 years ago is equal to present age of Danish

19x - 6 - 4 = 17x - 6

⇒ 2x = 4

⇒ x = 2

Present age of Keshav = (19 × 2) - 6 = 32 years

Present age of Danish = (17 × 2) - 6 = 28 years

Sum of their ages = 32 + 28 = 60

∴ The sum of their ages is 60.

The ratio of ages of Rahul and his wife after 7 years from now will be 7 ∶ 6. If his wife was born 23 years ago, find the age of Rahul after 2 years?

  1. 25
  2. 30
  3. 28
  4. 40

Answer (Detailed Solution Below)

Option 2 : 30

Problem on Age Question 13 Detailed Solution

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Given:

Wife was born 23 years ago (which means her present age is 23 years

Ratio of ages of Rahul and his wife 7 years from now will be 7 : 6

Calculation:

Let the present age of husband be x years.

Age of husband 7 years hence = x + 7

Present age of wife = 23 years

Age of wife after 7 years = 30 years

According to the question,

Ratio of ages of husband and wife 7 years from now = 7 : 6

⇒ (x + 7)/30 = 7/6

⇒ x + 7 = 35

⇒ x = 28 years

∴ Age of Rahul after 2 years = 30

Before 6 years, the ratio between the age of Radha and Ram is 5 : 8. The difference between the age of Ram and Radha is 6 years. After how many years, the ratio of their age will become 13 : 16?

  1. 9 years
  2. 12 years
  3. 7 years
  4. 10 years

Answer (Detailed Solution Below)

Option 4 : 10 years

Problem on Age Question 14 Detailed Solution

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Given,

Let present age of Radha and Ram be a years and b years respectively.

⇒ (a - 6) : (b - 6) = 5 : 8

⇒ 8a - 48 = 5b - 30

⇒ 8a - 5b = 18

Then,

⇒ b - a = 6

Solving,

a = 16 years and b = 22 years

Then,

⇒ (16 + ?) : (22 + ?) = 13 : 16

⇒ 256 + 16? = 286 + 13?

⇒ ? = 10

∴ after 10 years ratio will become 13 :16.

The ratio of the ages of A, B and C, 5 years ago, was 4 : 5 : 7. The sum of their present ages is 135 years. What will be the sum of the ages (in years) of B and C, 3 years from now?

  1. 100
  2. 96
  3. 106
  4. 112

Answer (Detailed Solution Below)

Option 3 : 106

Problem on Age Question 15 Detailed Solution

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Given:

5 years ago, ratio of ages of A, B and C = 4 : 5 : 7.

Sum of their present ages = 135 years.

Concept used:

Total = Average × Number of entities

Calculation:

Let the common ratio be Q.

So, 5 years ago, the ages of A, B, and C are 4Q, 5Q, and 7Q respectively.

Now, their present ages are (4Q + 5), (5Q + 5), and (7Q + 5) respectively.

According to the question,

(4Q + 5) + (5Q + 5) + (7Q + 5) = 135

⇒ 16Q + 15 = 135

⇒ 16Q = 135 - 15

⇒ 16Q = 120

⇒ Q = 7.5

The present age of B = (5 × 7.5 + 5) = 42.5 years

The present age of C = (7 × 7.5 + 5) = 57.5 years

Now, 3 years from now, the sum of the ages of B and C

⇒ (42.5 + 3) + (57.5 + 3)

⇒ 106 years

∴ After 3 years from now, the sum of the ages of B and C will be 106 years.

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