Linear Inequations MCQ Quiz - Objective Question with Answer for Linear Inequations - Download Free PDF

Last updated on May 13, 2025

Latest Linear Inequations MCQ Objective Questions

Linear Inequations Question 1:

Number of integral values of x satisfying x2 - 4x - 21 > 0 and x2 - 9x + 8

  1. one 
  2. two 
  3. many 
  4. nil 

Answer (Detailed Solution Below)

Option 4 : nil 

Linear Inequations Question 1 Detailed Solution

Calculation

x² - 4x - 21 > 0:

(x-7)(x+3) > 0.

Solutions: x 7.

x² - 9x + 8

(x-1)(x-8)

Solutions: 1

Combine solutions: x 7, and 1

 

Intersection is 7

Integral values between 7 and 8: None.

Therefore, no integral values satisfy both inequalities.

Hence option 4 is correct

Linear Inequations Question 2:

The solution region of the inequality 2x + 4y ≤ 9 is:

  1. open half plane containing origin
  2. closed half plane containing origin
  3. open half plane not containing origin
  4. closed half plane not containing origin

Answer (Detailed Solution Below)

Option 2 : closed half plane containing origin

Linear Inequations Question 2 Detailed Solution

Concept:

Solution Region of an Inequality:

  • The solution region of an inequality is the set of all points that satisfy the inequality.
  • For linear inequalities, the solution region is typically a half-plane or a region bounded by lines.
  • The inequality given is: 2x + 4y ≤ 9.
  • We can rewrite the inequality as a line equation: 2x + 4y = 9 and plot it on the coordinate plane.
  • The solution region consists of all points that satisfy the inequality, which is typically one side of the line.

 

Calculation:

Given the inequality: 2x + 4y ≤ 9

First, rewrite the inequality as the equation of a line:

2x + 4y = 9

Now, solve for y:

4y = 9 - 2x

y = (9 - 2x) / 4

y = 9/4 - x/2

The slope of the line is -1/2 and the y-intercept is 9/4.

Plot the line y = (9 - 2x)/4 on the coordinate plane.

The solution region will be the area below this line since the inequality is ≤ (i.e., points that satisfy the inequality lie below or on the line).

Thus, the solution region is the half-plane below the line 2x + 4y = 9, including the line itself.

∴ The solution region is the region below and on the line 2x + 4y = 9.

Linear Inequations Question 3:

The solution set of the inequality 37 − (3x + 5) ≥ 9x − 8(x − 3) is

  1. (−∞, 2)
  2. (−∞, −2) 
  3. (−∞, 2]
  4. (−∞, −2] 

Answer (Detailed Solution Below)

Option 3 : (−∞, 2]

Linear Inequations Question 3 Detailed Solution

Calculation

Given;

Inequality: 37 - (3x + 5) ≥ 9x - 8(x - 3)

⇒ 37 - 3x - 5 ≥ 9x - 8x + 24

⇒ 32 - 3x ≥ x + 24

⇒ 32 - 24 ≥ x + 3x

⇒ 8 ≥ 4x

⇒ 4x ≤ 8

⇒ x ≤ 2

∴ The solution set is (-∞, 2].

Hence option 3 is correct.

Linear Inequations Question 4:

If x satisfies the inequality , then x lies in the interval

Answer (Detailed Solution Below)

Option 1 :

Linear Inequations Question 4 Detailed Solution

Calculation

Given:

⇒ 

⇒ 

⇒  x \geq \frac{11}{-3}\)

⇒   x \geq -\frac{11}{3}\)

⇒ 

∴ x lies in the interval

Hence option 1 is correct

Linear Inequations Question 5:

The solution of the inequality |3x - 4| ≤ 5 is

  1. [-1, 4]
  2. [1, ∞)
  3. [-1, 1]
  4. [0, 1]

Answer (Detailed Solution Below)

Option 1 :

Linear Inequations Question 5 Detailed Solution

Concept Used:

The absolute value inequality  can be written as .

Calculation

Given: The inequality is

⇒ 

∴ The solution of the inequality is .

Hence, option 1 is correct.

Top Linear Inequations MCQ Objective Questions

Write the solution of inequality .

Answer (Detailed Solution Below)

Option 1 :

Linear Inequations Question 6 Detailed Solution

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CALCULATIONS:

Given 

Therefore, option (1) is the correct answer.

Answer (Detailed Solution Below)

Option 3 :

Linear Inequations Question 7 Detailed Solution

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Concept:

Comparison using inequality:

For any two real numbers  and  if  then .

Calculation:

Use the given inequality and proceed as follows:

Therefore, we conclude that .

What is the solution set for 0

  1. (−6, 6)
  2. (−6, 0)
  3. (0, 6)
  4. (−∞, −6)

Answer (Detailed Solution Below)

Option 2 : (−6, 0)

Linear Inequations Question 8 Detailed Solution

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Concept:

Rules for Operations on Inequalities:

  • Adding the same number to each side of an inequality does not change the direction of the inequality symbol.
  • Subtracting the same number from each side of an inequality does not change the direction of the inequality symbol.
  • Multiplying each side of an inequality by a positive number does not change the direction of the inequality symbol.
  • Multiplying each side of an inequality by a negative number reverses the direction of the inequality symbol.
  • Dividing each side of an inequality by a positive number does not change the direction of the inequality symbol.
  • Dividing each side of an inequality by a negative number reverses the direction of the inequality symbol.

 

Calculation

Given: 0

Multiply by 2 in above inequality (Here 2 is a positive number so the direction of the inequality does not change)

⇒ 0

⇒ −6 ∴ x lies in (−6, 0)

Solve the following in equations

  1. (1, 2]
  2. (1, 3)
  3. (1, 3]
  4. (1, 4]

Answer (Detailed Solution Below)

Option 3 : (1, 3]

Linear Inequations Question 9 Detailed Solution

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Concept:

Rules for Operations on Inequalities:

  • Adding the same number to each side of an inequality does not change the direction of the inequality symbol.
  • Subtracting the same number from each side of an inequality does not change the direction of the inequality symbol.
  • Multiplying each side of an inequality by a positive number does not change the direction of the inequality symbol.
  • Multiplying each side of an inequality by a negative number reverses the direction of the inequality symbol.
  • Dividing each side of an inequality by a positive number does not change the direction of the inequality symbol.
  • Dividing each side of an inequality by a negative number reverses the direction of the inequality symbol.

 

Calculation:

Given:

Multiplying each side of an inequality by a negative number (-1/3) reverses the direction of the inequality symbol.

, Here x – 1 ≠ 0 ⇒ x ≠ 1

Hence the solution set of the given in equations is (1, 3]

The solution of  is :

  1. x  ∈ (−∞ ,2)
  2. x  ∈ (∞,2)
  3. x  ∈ (2,∞)
  4. x  ∈ (2,∞)

Answer (Detailed Solution Below)

Option 1 : x  ∈ (−∞ ,2)

Linear Inequations Question 10 Detailed Solution

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Concept:

Solution Set: The set of all possible values of x.

When (a > 0 and b 0) then 

When (a > 0 and b > 0) or (a ">0\)

Calculation:

Here, 

So, x - 2

⇒ x

∴ x ∈ (-∞ , 2)

The solution of the inequality  \frac{x}{2} + 1\)will be - 

  1. x > 4
  2. x > -4
  3. x < -4
  4. -4 < x >4

Answer (Detailed Solution Below)

Option 3 : x < -4

Linear Inequations Question 11 Detailed Solution

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CALCULATION:

Given  \frac{x}{2} + 1\)

1\)

1\)

1\)

1\)

4\)

Therefore option (3) is the correct answer.

The Minimum value of P = 6x + 16y subject to constraints x ≤ 40, y ≤ 20 and x, y ≥ 0 is

  1. 240
  2. 320
  3. 0
  4. None of these

Answer (Detailed Solution Below)

Option 3 : 0

Linear Inequations Question 12 Detailed Solution

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Calculation:

Here, constraints: x ≤ 40, y ≤  20 and x, y ≥ 0 

 

We get minimum value of P, only when x = 0 and y = 0

So, P = 6(0) + 16(0) = 0

Hence, option (3) is correct.

If |x2 - 3x + 2| > x2 - 3x + 2, then which one of the following is correct?

  1. x ≤ 1 or x ≥ 2
  2. 1 ≤ x ≤ 2
  3. 1 < x < 2
  4. x is any real value except 3 and 4

Answer (Detailed Solution Below)

Option 3 : 1 < x < 2

Linear Inequations Question 13 Detailed Solution

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Concept:

If f (x) = |x|, then

Calculation:

Given: |x2 - 3x + 2| > x2 - 3x + 2

Case-1: If x ≥ 0

⇒ x2 - 3x + 2 > x2 - 3x + 2

∴ No real value of x satisfies the above equation.

Case-2:- If x

⇒ - (x2 - 3x + 2) > x2 - 3x + 2

⇒ x2 - 3x + 2

⇒ (x - 1) (x - 2) ⇒ 1

The constraints –x + y ≤ 1, −x + 3y ≤ 9 and x, y ≥ 0 defines on

  1. Bounded feasible space
  2. Unbounded feasible space
  3. Both unbounded and bounded feasible space
  4. None of the above

Answer (Detailed Solution Below)

Option 2 : Unbounded feasible space

Linear Inequations Question 14 Detailed Solution

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Concept:

First, graph the "equals" line, then shade in the correct area.

There are three steps:

  • Rearrange the equation so "y" is on the left and everything else on the right.
  • Plot the "y = " line (make it a solid line for y ≤ or y ≥, and a dashed line for y )
  • Shade above the line for a "greater than" (y > or y ≥) or below the line for a "less than" (y

 

Calculation:

Given: The constraints –x + y ≤ 1, −x + 3y ≤ 9 and x, y ≥ 0

–x + y ≤ 1

⇒ y ≤ 1 + x

Hence shade below the line.

−x + 3y ≤ 9

3y ≤ 9 + x

⇒ y ≤ 3 + x/3

Hence shade below the line.

We can see through above graph region is unbounded feasible space

If , what is the possible range of values for x?

  1. x < 3 OR x > 4
  2. x < 0 OR x > 12
  3. x < 3 OR x > 0
  4. x < 0 OR x > 3

Answer (Detailed Solution Below)

Option 2 : x < 0 OR x > 12

Linear Inequations Question 15 Detailed Solution

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Concept:

Rules for Operations on Inequalities:

  • Adding the same number to each side of an inequality does not change the direction of the inequality symbol.
  • Subtracting the same number from each side of an inequality does not change the direction of the inequality symbol.
  • Multiplying each side of an inequality by a positive number does not change the direction of the inequality symbol.
  • Multiplying each side of an inequality by a negative number reverses the direction of the inequality symbol.
  • Dividing each side of an inequality by a positive number does not change the direction of the inequality symbol.
  • Dividing each side of an inequality by a negative number reverses the direction of the inequality symbol.

 

Calculation:

Given:

Multiplying each side of an inequality by a negative number reverses the direction of the inequality symbol.

0\), Here x ≠ 0

∴ x 12

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