Coding Decoding MCQ Quiz - Objective Question with Answer for Coding Decoding - Download Free PDF

Conditions:

(i) If the first element is a symbol and the last a number, the codes for these two (the first and the last elements) are to be interchanged.
(ii) If the first element is an odd number and the last an even number, the first and last elements are to be coded as ©

(iii) If both the second and third elements are perfect squares, the third element is to be coded as the code for the second element.

Given- 7 2 4 @ 5

The first element is 7 (an odd number).
The last element is 5 (an odd number).
The second element is 2 (not a perfect square).
The third element is 4 (a perfect square, 2*2=4).

Rule No. (i): This condition does not apply because the first element (7) is a number, not a symbol.
Rule No. (ii): This condition does not apply because the last element (5) is an odd number, not an even number.
Rule No. (iii): This condition does not apply because the second element (2) is not a perfect square, even though the third element (4) is.

Since none of the given conditions apply, the codes for the respective number/symbol are to be followed directly as given in the table.

The code for 7 is P.
The code for 2 is T.
The code for 4 is B.
The code for @ is F.
The code for 5 is J.

Thus, '7 2 4 @ 5' is coded as → P T B F J.

Hence, the correct answer is "Option 3".

Conditions:

(i) If the first element is a symbol and the last a number, the codes for these two (the first and the last elements) are to be interchanged.

(ii) If the first element is an odd number and the last an even number, the first and last elements are to be coded as ©

(iii) If both the second and third elements are perfect squares, the third element is to be coded as the code for the second element.

Given- 5 & 3 @ 7 % 2

The first element is 5 (an odd number).
The last element is 2 (an even number).
The second element is & (a symbol, not a perfect square).
The third element is 3 (not a perfect square).

Rule No. (i): This condition does not apply because the first element (5) is a number, not a symbol.

Rule No. (ii): This condition applies because the first element (5) is an odd number and the last element (2) is an even number. So, the first and last elements will be coded as ©.

Rule No. (iii): This condition does not apply because neither the second element (&) nor the third element (3) are perfect squares.
Based on the applicable rule (ii), the first and last elements are coded as ©.

The code for & is M.

The code for 3 is D.

The code for @ is Z.

The code for 7 is W.

The code for % is P.

Thus, '5 & 3 @ 7 % 2' is coded as → © M D Z W P ©.

Hence, the correct answer is "Option 4".

Given:

(ii) If the first element is an odd number and the last an even number, the first and last elements are to be coded as ©

(iii) If both the second and third elements are perfect squares, the third element is to be coded as the code for the second element.

Given- 7 2 @ 1 3 &

Rule No. (i) This condition does not apply because the first element (7) is a number, not a symbol.

Rule No. (ii) This condition does not apply because while the first element (7) is an odd number, the last element (&) is a symbol, not an even number.

Rule No. (iii) This condition does not apply because neither the second element (2) nor the third element (@) are perfect squares.

So, the code for  7 2 @ 1 3 & is 

The code for 7 is W.

The code for 2 is A.

The code for @ is Z.

The code for 1 is R.

The code for 3 is T.

The code for & is M.

Thus, '7 2 @ 1 3 &' is code 'W A Z R T M'.

Hence, the correct answer is "Option 2".

Logic: From the above-given words we have to consider the code and find the code for "SILICA".

For, MUSIC: 37489

For, GHAZALS: 6051524

Now for, SILICA:

As the obtained code is "482895"

Therefore, the correct answer should be "Option2: 482895".

The logic followed here is:

For, ‘PAIDY’ is written as ‘NYGBW’,

For, ‘FORST’ is written as ‘DMPQR’,

Similarly, for HARKG

So, 'HARKG' will be written as 'FYPIE'.

Hence, the correct answer is "Option 2".

The logic followed here is :-

'LEMON' is written as 'ELMNO'.

Similarly,

'CLUSTER' will be written as :

Hence, the correct answer is "CELRSTU".

We know that,

The pattern followed here is as follows,

Similarly,

Thus SWAN is written as 1923114.

Hence, “4” is the last digit of SWAN.

The pattern followed here is:

According to the alphabetical positions of the letters,

Logic is: Sum of the place value of the letters × Number of letters in the word

 SEND = 19 + 5 + 14 + 4 = 42 × 4 = 168

Similarly,

PURSE = 16 + 21 + 18 + 19 + 5 = 79 × 5 = 395 

Hence, ‘395’ is the correct answer.

Logic : Letters of the word are arranged in ascending order according to English alphabetic series.

So,

• 'BEHOLD’ is written as 'BDEHLO'

• 'INDEED' is written as 'DDEEIN'

Similarly,

• 'COURSE' is written as :​

Hence, "CEORSU" is the correct answer.

The table is alphabets place value:

The pattern followed here is:

Step 1: Vowels place values coded as numbers. 

Step 2: Consonants opposite alphabet place value code as numbers.

Step 3: Then this coded number is arranged in reverse order.

‘CROWD’ is coded as 23415924

And,

‘TRHICK’ is coded as 162491997

Similarly,

‘FRUGAL’ be coded

Hence, ‘FRUGAL’ is coded as "1512021921".

The pattern followed here is:

The word is coded as the total letter number of letters present in the word.

6219 means ‘Sachin is a cricketer’

And,

2646 means ‘He played from Mumbai’

Similarly,

‘Mumbai is very famous’ means ?

Hence, the correct answer is "6246".

The position of letters according to the English alphabet series:

Logic: + 3 every letter then arranged alphabetical order.

'CONSULT' is written as 'FOQRVWX'

Similarly,

'MAGNETS' is written as '?'

Hence, the correct answer is "DHJPQVW".

Note:  This is SSC GD Previous year question paper and given answer as per the official answer key.

The letters are replaced by the place value of their reverse letter and then the numbers are added together to obtain the code.

Similarly,

Hence, ‘61’ is the correct answer.

Mistake PointsTOUCH = 20 + 15 + 21 + 3 + 8 =  67 and 67 + 1 = 68

ERROR = 5 + 18 + 18 + 15 + 18 = 74 and  74 + 1 = 75

75 is not in the options so the logic is different here.

The logic here is not sum of positional value + 1, but the logic here is sum of opposite positional value of letters.

The logic followed here is:

 ‘ARROW’ is coded as ‘FOOSE’

‘GERM’ is coded as ‘THOR’

So, by observing the pattern, we can conclude that,

 A = F, R = O, O = S, W = E, G = T, E = H, R = O and M = R.

Now, we have to find the code for MOWER

As the codes of all the letters have been given in the question,

M = R, O = S, W = E, E =H, and R = O

Hence,

‘MOWER’ = ?

Hence, MOWER is coded as ‘RSEHO’.

According to the given information

‘Country’ is coded as 7.

Hence, ‘7’ is the correct answer.